3[7x-4(x-3)]+1=16

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Solution for 3[7x-4(x-3)]+1=16 equation: 


Simplifying
3[7x + -4(x + -3)] + 1 = 16

Reorder the terms:
3[7x + -4(-3 + x)] + 1 = 16
3[7x + (-3 * -4 + x * -4)] + 1 = 16
3[7x + (12 + -4x)] + 1 = 16

Reorder the terms:
3[12 + 7x + -4x] + 1 = 16

Combine like terms: 7x + -4x = 3x
3[12 + 3x] + 1 = 16
[12 * 3 + 3x * 3] + 1 = 16
[36 + 9x] + 1 = 16

Reorder the terms:
36 + 1 + 9x = 16

Combine like terms: 36 + 1 = 37
37 + 9x = 16

Solving
37 + 9x = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-37' to each side of the equation.
37 + -37 + 9x = 16 + -37

Combine like terms: 37 + -37 = 0
0 + 9x = 16 + -37
9x = 16 + -37

Combine like terms: 16 + -37 = -21
9x = -21

Divide each side by '9'.
x = -2.333333333

Simplifying
x = -2.333333333

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